(1/3)(x-4)^2-3=0

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Solution for (1/3)(x-4)^2-3=0 equation: 


x in (-oo:+oo)

(1/3)*(x-4)^2-3 = 0

1/3*(x-4)^2-3 = 0

1/3*(x-4)^2-3 = 0

1/3*x^2-8/3*x+7/3 = 0

1/3*x^2-8/3*x+7/3 = 0

1/3*(x^2-8*x+7) = 0

x^2-8*x+7 = 0

DELTA = (-8)^2-(1*4*7)

DELTA = 36

DELTA > 0

x = (36^(1/2)+8)/(1*2) or x = (8-36^(1/2))/(1*2)

x = 7 or x = 1

1/3*(x-1)*(x-7) = 0

1/3*(x-1)*(x-7) = 0

( 1/3 )

1/3 = 0

x belongs to the empty set

( x-1 )

x-1 = 0 // + 1

x = 1

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 1, 7 }

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